48x^2-48x-63=0

Solution for 48x^2-48x-63=0 equation:

48x^2-48x-63=0

a = 48; b = -48; c = -63;
Δ = b2-4ac
Δ = -482-4·48·(-63)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-120}{2*48}=\frac{-72}{96}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+120}{2*48}=\frac{168}{96}
=1+3/4
$